(c) Find its maximum or minimum value. g(x) =

Algebra
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g(x) = 3x2 − 24x + 49

(c) Find its maximum or minimum value. 

g(x) = 
Jul 8th, 2015

Thank you for the opportunity to help you with your question!

A positive number in front of x² means a mini mum value

If you know differentiation then g(x) = 3x²24x+49

g'(x) = 6x -24

For minimum g'(x)= 0

6x -24 =0

6x = 24

x =4

Minimum = 3 (4)² – 24 (4) + 49

= 48 -96 + 49

= 1


Or by completing the square g(x) = 3x²24x+49 = 3 ( x²- 8x) + 49

= 3 [ (x -4)² -16] + 49

Minimum occurs when x=4 and value is 3 [ (4 -4)² -16] + 49

= -48 + 49

=1                                                    


Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 8th, 2015

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