Mary is six years older than little Timmy. Jane is exactly twice Timmy's age. The sum of all three is 34. Find the age of MARY
a. x=7 b. x=21 c. x=4 d. x=-11 ??????
I think the question is the about the age of Timmy and not Mary. Let the age of Timmy be 'x'
x+6+x+2x = 34
4x+6 = 34
x = 28/4 = 7
Note: So mary's age = 13 and Jane's age = 14
how does 4x+6=34????
NVM NVM NVM
.Tim's age = x; Mary's age = x+6, Jane's age = 2x
Given the sum of the ages = 34
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