Finding a sinusoidal function

Mathematics
Tutor: None Selected Time limit: 1 Day

The curve above is the graph of a sinusoidal function. It goes through the point  and . Find a sinusoidal function that matches the given graph. 

Jul 9th, 2015

Thank you for the opportunity to help you with your question!

Where is the curve put it down on the comment i will give you the answer ok ......

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 9th, 2015

16.png 


It goes through the point (3,1)


Hopefully it uploads correctly this time, thanks!

Jul 9th, 2015

16.png 


It goes through the point (3,1)


Hopefully it uploads correctly this time, thanks!

Jul 9th, 2015

16.png 


It goes through the point (3,1)


Hopefully it uploads correctly this time, thanks!

Jul 9th, 2015

16.png 


It goes through the point (3,1)


Hopefully it uploads correctly this time, thanks!

Jul 9th, 2015

Just put it now .....;

Jul 9th, 2015
Jul 9th, 2015

Every time I reply to this thread it refreshes the page..I'm sorry for all the duplicate comments. Are you able to see the png?

Jul 9th, 2015

Sorry for late i just didn't saw the graph ......;

the function is : 

f(x) = - cos(x(pi/3)) 

Please each time you have any other homework invite me or ask me directly i will give you the best answer 

Good luck 

Jul 9th, 2015

Thanks Karim! 

I can tell by the graph that the Amplitude is 1 and I know to find B is 2pi/absolute value of B. Do you mind explaining how you were able to find -Cos(x(pi/3))? Thanks :)

Jul 9th, 2015

ok we know :  f(x) =  A cos(kx) - E 

so :  E = 0 

and :   A = - 1 

and :   k = 6  

so :  2pi/k = 6 

so :  k = 2pi/6 

so : k = pi/3

so we have just to put each terme on here place : 

so :f(x) =  -Cos(xpi/3)

is clear now

Jul 9th, 2015

ok we know :  f(x) =  A cos(kx) - E 

so :  E = 0 

and :   A = - 1 

and :   k = 6  

so :  2pi/k = 6 

so :  k = 2pi/6 

so : k = pi/3

so we have just to put each terme on here place : 

so :f(x) =  -Cos(xpi/3)

is clear now ?? 

Jul 9th, 2015

Great explanation! I can do the rest now thank you very much!

Jul 9th, 2015

Great that s what i want , but test is cos() or sin() ok , and good luck 

Jul 9th, 2015

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