##### Find the maximum or minimum value of the function. (Round your answer to two dec

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Find the maximum or minimum value of the function. (Round your answer to two decimal places.)

f(s) = s2 − 1.2s + 16

Oct 18th, 2017

Thank you for the opportunity to help you with your question!

f(s) = s^2-1.2s+16

First derivative of f(s) = 2s-1.2

0= 2s-1.2

s= 1.2/2

s = 0.6

taking 2nd derivative of f(s)

2nd derivative of f(s) = 2  which is > 0 so this function has the minimum value

f(0.6) = 0.6^2-1.2(0.6)+16

f(0.6)= 15.64

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 9th, 2015

the answer is not clear can you please specify

Jul 9th, 2015

ye sure

Jul 9th, 2015

to find the max or minimum value of any function we need to find its derivatives , first of all you have to find the first derivative after that you put that first derivative equation equal to 0 and find the value of variable , then you take 2nd derivative and put that value in 2nd derivative equation , if you get >0 then its minimum and if it is <0 then you have maximum value

Jul 9th, 2015

the answer is a number but not 0

Jul 9th, 2015

yes the answer is 2 which is greater than 0 , I mentioned it before 2 >0 which means function has minimum value

Jul 9th, 2015

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Oct 18th, 2017
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Oct 18th, 2017
Oct 19th, 2017
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