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Answer:young's modulus is a ratio of tensile stress and tensile strain . which gives , E = (F/A) /( del L/L) = FL/A 'del L' we deduce , 'del L'= FL/AE in ques. m=190 kg . , F = mg = 190x9.8 N =1862 N A=area of wire = 2.00x10^-5 m2 L= 3.7 m E = 8.00x10^10 N/m2 so , putting value we get increase in length 'del L' = FL/AE=(1862x3.7)/( 2.00x10^-5 x8.00x10^10) m = 4.3059x 10^-3 m
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