Young's Modulus Example (Increase In Length)

Physics
Tutor: None Selected Time limit: 1 Day

190-kg load is hung on a wire of length of 3.70 m, cross-sectional area 2.00  10-5 m2, and Young's modulus 8.00  1010 N/m2. What is its increase in length?

Jul 9th, 2015

Thank you for the opportunity to help you with your question!

Answer:young's modulus is a ratio of tensile stress and tensile strain . 
which gives , E = (F/A) /( del L/L) = FL/A 'del L' 
we deduce , 'del L'= FL/AE 
in ques. m=190 kg . , F = mg = 190x9.8 N =1862 N 
A=area of wire = 2.00x10^-5 m2 
L= 3.7 m 
E = 8.00x10^10 N/m2 
so , putting value we get increase in length 'del L' = FL/AE=(1862x3.7)/( 2.00x10^-5 x8.00x10^10) m = 4.3059x 10^-3 m

Best of luck dear..........................

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 9th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
Jul 9th, 2015
...
Jul 9th, 2015
Mar 23rd, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer