Young's Modulus Example (Increase In Length)

Physics
Tutor: None Selected Time limit: 1 Day

190-kg load is hung on a wire of length of 3.70 m, cross-sectional area 2.00  10-5 m2, and Young's modulus 8.00  1010 N/m2. What is its increase in length?

Jul 9th, 2015

Thank you for the opportunity to help you with your question!

Answer:young's modulus is a ratio of tensile stress and tensile strain . 
which gives , E = (F/A) /( del L/L) = FL/A 'del L' 
we deduce , 'del L'= FL/AE 
in ques. m=190 kg . , F = mg = 190x9.8 N =1862 N 
A=area of wire = 2.00x10^-5 m2 
L= 3.7 m 
E = 8.00x10^10 N/m2 
so , putting value we get increase in length 'del L' = FL/AE=(1862x3.7)/( 2.00x10^-5 x8.00x10^10) m = 4.3059x 10^-3 m

Best of luck dear..........................

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 9th, 2015

Are you studying on the go? Check out our FREE app and post questions on the fly!
Download on the
App Store
...
Jul 9th, 2015
...
Jul 9th, 2015
Dec 4th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer