onfidence interval used to estimate the population proportion.

Statistics
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In a clinical test with 8900 subjects, 4450 showed improvement from the treatment. Find the margin of error for the 99% confidence interval used to estimate the population proportion.    

Jul 10th, 2015

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E=.0137  computed as follows:

E= z(.005)*sqrt(pq/n)

 z=2.58   p=4450/ 8900=.5  q=.5

E=2.58*sqrt(.5*.5/8900)= .0137

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Jul 10th, 2015

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