estimate a population proportion

Statistics
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Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places.

95% confidence; n = 2015, x = 1631      
Jul 10th, 2015

Thank you for the opportunity to help you with your question!

E=z(.025)*sqrt(pq/n)

z(.025)= 1.96 p=1631/2015=.8094 q=.1906  n=2015 

Substitute the above values to the formula to get E=.0171

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 10th, 2015

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