find a confidence interval for the population standard deviation σ.

label Statistics
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account_balance_wallet $5 Use the given degree of confidence and sample data to find a confidence interval for the population standard deviation σ. Assume that the population has a normal distribution. Round the confidence interval limits to the same number of decimal places as the sample standard deviation. College students' annual earnings: 98% confidence; n = 9, x =$3705, s = \$841
Jul 10th, 2015

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98% CI for  σ =( SQRT((n-1)s^2/chi^2(right) ,  SQRT((n-1)s^2/chi^2(left)

n-1=8 ;

s^2=707281

chi^2(right)=20.09

chi^2(left)= 1.65

Substituting the values to the formula above, gives

98% CI :  531 < σ < 1854

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 10th, 2015

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Jul 10th, 2015
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Jul 10th, 2015
Sep 19th, 2017
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