sample size of population

Statistics
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In a certain population, body weights are normally distributed with a mean of 152 pounds and a standard deviation of 26 pounds. How many people must be surveyed if we want to estimate the percentage who weigh more than 180 pounds? Assume that we want 96% confidence that the error is no more than 2.5 percentage points.    

Jul 10th, 2015

Thank you for the opportunity to help you with your question!

P(x>180)= P(z> (180-152)/26)=.14

p=.14  q=.86   z(.02)= 2.054

n= z^2*.14*.86/.025^2 = 812.5 round up to 813

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Jul 10th, 2015

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