##### Find a 98% confidence interval for the population standard deviation σ

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Use the given degree of confidence and sample data to find a confidence interval for the population standard deviation σ. Assume that the population has a normal distribution. Round the confidence interval limits to one more decimal place than is used for the original set of data.

The amounts (in ounces) of juice in eight randomly selected juice bottles are:
15.0  15.9  15.2  15.7
15.0  15.8  15.4  15.4
Find a 98% confidence interval for the population standard deviation σ.
Jul 10th, 2015

To find 98% confidence interval for the population standard deviation σ, we need the following:

s^2; n-1, Chi^2(right),Chi^2(left) to plug in the following formula:

(Sqrt((n-1)s^2/Chi^2(right)), Sqrt((n-1)s^2/Chi^2(right))

s^2=.1221; n=1 =7,Chi^2(right)(.01,7)=18.48  Chi^2(left)= 1.24

98% confidence interval= (0.2088 < SD < 0.9167)

Jul 10th, 2015

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Jul 10th, 2015
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Jul 10th, 2015
Dec 7th, 2016
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