Physics relativity 9

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A bomb is designed to explode 2.00 s after it is armed. The bomb is launched from earth and accelerated to an unknown final speed. After reaching its final speed, however, the bomb is observed by people on earth to explode 2.90 s after it is armed. What is the final speed of the bomb just before it explodes?

Jul 10th, 2015

Thank you for the opportunity to help you with your question!

t' = 1/gamma t 

gamma = 2.9/2 =1.45 =1/sqrt(1-b^2) 

1-b^2 = 1/1.45^2 =  0.4756 

b = 0.724 

V = 0.724 c = 2.17 x10^8 m/s 

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 10th, 2015

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Jul 10th, 2015
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Jul 10th, 2015
Jun 26th, 2017
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