Description
A bomb is designed to explode 2.00 s after it is armed. The bomb is launched from earth and accelerated to an unknown final speed. After reaching its final speed, however, the bomb is observed by people on earth to explode 2.90 s after it is armed. What is the final speed of the bomb just before it explodes?
Explanation & Answer
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t' = 1/gamma t
gamma = 2.9/2 =1.45 =1/sqrt(1-b^2)
1-b^2 = 1/1.45^2 = 0.4756
b = 0.724
V = 0.724 c = 2.17 x10^8 m/s
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