An electron gun inside a computer monitor sends an electron toward the screen at a speed of 1.20 × 10^{8} m/s. If the mass of the electron is 9.109 × 10^{–31} kg, what is the magnitude of its relativistic momentum?

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gamma = 1/sqrt (1-v^2/c^2)

gamma = 1/sqrt {(1-(1.2*1.2/9)}

gamma = 1.091

change of momonetum =gamma mv = 1.091 *9.11*10^-31 * *1.2* 10^8

= 1.19 *10^-22 kgm/s

magnitude of its relativistic momentum=Mv= ( 1.20 * 10^{8} )*( 9.109 * 10-^{31})

=1.09*10^-22 kg-m/s Answer

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