physics relativity 11

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A subatomic particle X spontaneously decays into two particles, A and B, each of rest energy 1.40 × 102 MeV. The particles fly off in opposite directions, each with speed 0.827c relative to an inertial reference frame S.

Reference: Ref 28-1

Determine the kinetic energy of particle (relative to frame S).
Jul 10th, 2015

Thank you for the opportunity to help you with your question!

gamma = 1/sqrt(1-b^2) = 1.779

Ke = gamma mc^2 - mc^2 

=0.779*mc^2 = 0.779*140MeV = 109 MeV


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Jul 10th, 2015

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Jul 10th, 2015
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