I can't figure out the work up to the answer,

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The Milky Way galaxy is a part of a group of galaxies called the Local Group. The proper distance from the Milky Way, on one side of the Local Group, to the M31 galaxy on the other side is approximately 2.4 × 106 light-years. How long (in years) would it take a spaceship traveling at 0.999c to travel this distance according to travelers onboard?

Jul 10th, 2015

Thank you for the opportunity to help you with your question! the solution is as such:

1 light year = 9.4605284 × 1015 meters

so, total distance D= 2.4 × 106 * 9.4605284 × 1015 meters

v= 0.999c where c= 3 × 108 meters per sec

now time = D/ v

so we get, time t= 7.5684 × 1013 seconds

Please let me know if you need any clarification. I'm always happy to answer your questions.awaiting a positive feedback. It was lovely helping you. Please do contact or text me directly for more work assistance. Looking forward to help you again.
Jul 10th, 2015

message me in my inbox if u have more questions

Jul 10th, 2015

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