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Algebra
Tutor: None Selected Time limit: 1 Day

Jul 10th, 2015

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Let ( x0 , y0 ) be any point on the parabola.

 Find the distance between (x0 , y0) and the focus. Then find the distance between (x0 , y0) and directrix. Equate these two distance equations and the simplified equation in x0 and y0 is equation of the parabola.

The distance between (x0 , y0) and (2, -1) is

sqrt((x-2)^2 + (y-(-1))^2)

(x0 , y0) and the directrix, = -1/2 is

y0– -1/2|.

Equate the two distance expressions and square on both sides.

(x-2)^2 + (y-(-1))^2) = (y+1/2)^2

answer is D.

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 10th, 2015

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