Number of hours the passenger train traveled before the cattle train caught up


label Mathematics
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

A passenger train left Washington and traveled toward the fueling station at an average speed of 15 mph.  A cattle train left six hours later and traveled in the same direction but with an average speed of 24 mph.  Find the number of hours the passenger train traveled before the cattle train caught up.

Jul 11th, 2015

Thank you for the opportunity to help you with your question!

speed of passenger train=15mph

total hours travelled by passenger train=x=?

speed of cattle train=24mph

total hours travelled by cattle train=x-6 (because train left 6 hours later than the passenger train)

distance of passenger train=distance of cattle train (has to be in order for one train to catch up other)

speed(passenger)xtime(passenger=speed(cattle)xtime(cattle)

15x=24(x-6)

x=16hours.

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 11th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Jul 11th, 2015
...
Jul 11th, 2015
Nov 22nd, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer