Can someone please help with the below question?

label Calculus
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

Thank you for the opportunity to help you with your question!

lnx =e^y +(x^2+y^3)^2-2

dy/dx(lnx ) = dt/dy(e^y +(x^2+y^3)^2-2)

dy/dx= 0 + dy/dx(x^4+y^6+2x^2 y^3)

dy/dx= 4x^3+4x y^2

dy/dx=4+6(1)^2 (0)^2

dy/dx =4

by chain rule

dy/dt = dx/dt * dy/dx

dy/dt = -2 *4

dy/dt = -8

please go to your home page .click on promotion who has a heart icon add my name Asim Reh or my referral link https :// Reh?aid=Asim Reh in the open window and promote me we both will get 10$ by study pool promote and best me
Jul 14th, 2015

How did you get -8?

My answer is 6...see steps below, did I miss a step? Please advise. Thanks

/x=e^ydy/dx+2(x^2+y^3)(2x+3y^2dy/dx). Put x=1 and y=0: 1=dy/dx+2(1+0)(2+0), so dy/dx=1-4=-3.


Jul 14th, 2015

dear i think my answer is more correct

Jul 15th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
Jul 14th, 2015
Jul 14th, 2015
Oct 19th, 2017
Mark as Final Answer
Unmark as Final Answer
Final Answer

Secure Information

Content will be erased after question is completed.

Final Answer