physics question 1 hw 20

Physics
Tutor: None Selected Time limit: 1 Day

Molybdenum has a work function of 4.2 eV. Find the cutoff wavelength for the photoelectric effect. The speed of light is 3 × 108 m/s and Planck’s constant is 6.626 × 10−34 J · s. Answer in units of nm.

Calculate the stopping potential if the incident light has a wavelength of 109 nm. Answer in units of V.

Jul 14th, 2015

Thank you for the opportunity to help you with your question!

For part (b), the wavelength of the incident light is 180 nm, hence its energy is:

E = hc/λ = (4.135x10^-15 eV-s)(3x10^8 m/s)/(180x10^-9m)

= 6.89 eV

Since this energy exceeds the work function, the incident light will be able to remove electrons.

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Jul 14th, 2015

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