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What is the de Brogile wavelength of an electron that strikes the back of the face of a TV screen at 0.1 the speed of light? The speed of light is 2.998 × 108 m/s. Answer in units of m.
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The de Broglie wavelength
L=(h/mv)sqrt(1- (v/c)^2)
h= Planck's constant (6.63 E − 34 joule-seconds)
m - rest mass of the electron (9.10938188 E-31 kg)
v - velocity of the electron (m/s)
c - the speed of light (2.99 E+8 m/s)
L= (6.63 E − 34 x 10/ (9.10938 E-31 x 2.99 E+8)sqrt(1-(1/10)^2)
L=2.5E-11m
L=250 nm
L=(h/mv)sqrt(1- (v/c)^2)
h= Planck's constant (6.63 E − 34 joule-seconds)
m - rest mass of the electron (9.10938188 E-31 kg)
v - velocity of the electron (m/s)
c - the speed of light (2.99 E+8 m/s)
L= (6.63 E − 34 x 10/ (9.10938 E-31 x 2.99 E+8)sqrt(1-(1/10)^2)
L=2.5E-11m
L=250 nm
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