physics question 4+5

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1. Molybdenum has a work function of 4.2 eV. Find the cutoff wavelength for the photoelectric effect. The speed of light is 3 × 108 m/s and Planck’s constant is 6.626 × 10−34 J · s. Answer in units of nm.

2. Calculate the stopping potential if the incident light has a wavelength of 109 nm. Answer in units of V.

Jul 15th, 2015

Thank you for the opportunity to help you with your question!

wavelength = hc/E = 1240 eV*nm/4.2 eV = 295.24 nm 

E = hc/Labda = 1240 eV*nm/109 nm =  11.376 eV 

V = (11.376eV-4.2 eV)/e = 7.176 V

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Jul 15th, 2015

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