Can someone please help with the below question?

Calculus
Tutor: None Selected Time limit: 1 Day

revenue is found with he equation r=pq where p is the price charged and q is the quantity sold. If the price function is changing at a rate of 10 cents per day and the quantity sold is changing at -2 items per day. How is the revenue per day changing if the price is currently at $5 and the quantity sold is 100 items?

Jul 15th, 2015

Thank you for the opportunity to help you with your question!

r = pq

dr/dt = pdq/dt + qdp/dt

p = 5, dp/dt = 10 cents/day = 0.1USD/day, q = 100, dq/dt = -2/day

Hence, dr/dt = 5*-2+100*0.1

= -10+10

=0

It means that revenue is not changing or we can say that rate of change of revenue is zero.

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 15th, 2015

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Jul 15th, 2015
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Jul 15th, 2015
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