Description
Determine the kinetic energy of an electron that has a de Broglie wavelength equal to twice the diameter of the hydrogen atom. Assume that the hydrogen atom is a sphere of radius 5.3 × 10–11 m.
Explanation & Answer
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Lambda = h / p
p = mass x velocity
=> L = h /(mass x velocity)
=> mass x velocity = h/L
=> velocity = h/Lm
Plug in the known values for h L and m to get the electron's velocity
Plug the velocity into (1/2)mv^2 to get its kinetic energy.
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