Determine the kinetic energy of an electron that has a de Broglie wavelength equal to twice the diameter of the hydrogen atom. Assume that the hydrogen atom is a sphere of radius 5.3 × 10^{–11} m.

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Lambda = h / p p = mass x velocity => L = h /(mass x velocity) => mass x velocity = h/L => velocity = h/Lm Plug in the known values for h L and m to get the electron's velocity Plug the velocity into (1/2)mv^2 to get its kinetic energy.

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