Physics question 15 hw 21

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Determine the kinetic energy of an electron that has a de Broglie wavelength equal to twice the diameter of the hydrogen atom. Assume that the hydrogen atom is a sphere of radius 5.3 × 10–11 m.
Question 15 options:
Jul 15th, 2015

Thank you for the opportunity to help you with your question!

lambda = h / sqrt(2mK.E.) 

K.E=h^2/lamda^2 *2m

      =6.6*6.6*10^-68/5.3*5.3*10^-22 *2 *9.1*10^-31

     

      =13.6 ev

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Jul 15th, 2015

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