This exercise uses the population growth model. The population of a certain ci

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This exercise uses the population growth model. 

The population of a certain city was 146,000 in 2006, and the observed doubling time for the population is 18 years.
(a) Find an exponential model 
n(t) = n02t/a
 for the population t years after 2006. 
n(t) = 
 

(b) Find an exponential model 
n(t) = n0ert
 for the population t years after 2006. (Round your r value to four decimal places.) 
n(t) = 
Jul 15th, 2015

Thank you for the opportunity to help you with your question!

(a)  n(t) = 146,000 2^(t/18)

(b)  n(t) = 146,000 e ^(0.0385t)

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 15th, 2015

thank you for answering my question

146,000 (multiply)2^(t/18) was not sure is I multiply

Jul 15th, 2015

if you could please tell me the correct way to enter in the answer

Thanks

Jul 15th, 2015

can you try this:
(146,000)(2^(t/18))

Jul 15th, 2015

is the t/18 a exponet

Jul 15th, 2015

yes the whole t/18 is exponent, something like this:

     t/18

2

Jul 15th, 2015

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Jul 15th, 2015
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