##### This exercise uses the population growth model. The population of a certain ci

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This exercise uses the population growth model.

The population of a certain city was 146,000 in 2006, and the observed doubling time for the population is 18 years.
(a) Find an exponential model
n(t) = n02t/a
for the population t years after 2006.
n(t) =

(b) Find an exponential model
n(t) = n0ert
for the population t years after 2006. (Round your r value to four decimal places.)
n(t) =
Jul 15th, 2015

(a)  n(t) = 146,000 2^(t/18)

(b)  n(t) = 146,000 e ^(0.0385t)

Jul 15th, 2015

thank you for answering my question

146,000 (multiply)2^(t/18) was not sure is I multiply

Jul 15th, 2015

if you could please tell me the correct way to enter in the answer

Thanks

Jul 15th, 2015

can you try this:
(146,000)(2^(t/18))

Jul 15th, 2015

is the t/18 a exponet

Jul 15th, 2015

yes the whole t/18 is exponent, something like this:

t/18

Jul 15th, 2015

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Jul 15th, 2015
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Jul 15th, 2015
Oct 20th, 2017
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