The normal body temperature is 98.6°F. I

Algebra
Tutor: None Selected Time limit: 1 Day

 It has been determined experimentally that the constant in Newton's Law of Cooling is approximately k = 0.1947, assuming time is measured in hours. Suppose that the temperature of the surroundings is 65°F.

(a) Find a function T(t) that models the temperature t hours after death.
T(t) =

(b) If the temperature of the body is now 71°F, how long ago was the time of death? (Round your answer to the nearest whole number.) 
Jul 16th, 2015

Thank you for the opportunity to help you with your question!

According to Newton's Law of cooling
T(t) = Tamb  +(To -  Tamb)*e(-kt)

where To = initial temperature at t = 0  ; Tamb = ambient temp

(a) T(t) = 65+ (98.6-65)*e^(-0.1947t)  solving we get   T(t) = 65 + 33.6 * e^(-0.1947t)     Answer

(b) 71 = 65+33.6 * e^(-0.1947t)
e^(-0.1947t) = 0.178 ; or we can write  -0.1947 t = -1.7237
or we get t = 8.84  hours
t = 9 hours   (Answer)

Please find the solution enclosed here with. In case of any doubt please feel free to ask … If you need help in any assignment of math/ science … any online exam / discussion, Please contact for quick & quality services.
Jul 16th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
Jul 16th, 2015
...
Jul 16th, 2015
Dec 4th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer