##### The normal body temperature is 98.6°F. I

label Algebra
account_circle Unassigned
schedule 1 Day
account_balance_wallet \$5

It has been determined experimentally that the constant in Newton's Law of Cooling is approximately k = 0.1947, assuming time is measured in hours. Suppose that the temperature of the surroundings is 65°F.

(a) Find a function T(t) that models the temperature t hours after death.
 T(t) =

(b) If the temperature of the body is now 71°F, how long ago was the time of death? (Round your answer to the nearest whole number.)
Jul 16th, 2015

According to Newton's Law of cooling
T(t) = Tamb  +(To -  Tamb)*e(-kt)

where To = initial temperature at t = 0  ; Tamb = ambient temp

(a) T(t) = 65+ (98.6-65)*e^(-0.1947t)  solving we get   T(t) = 65 + 33.6 * e^(-0.1947t)     Answer

(b) 71 = 65+33.6 * e^(-0.1947t)
e^(-0.1947t) = 0.178 ; or we can write  -0.1947 t = -1.7237
or we get t = 8.84  hours

Please find the solution enclosed here with. In case of any doubt please feel free to ask … If you need help in any assignment of math/ science … any online exam / discussion, Please contact for quick & quality services.
Jul 16th, 2015

...
Jul 16th, 2015
...
Jul 16th, 2015
Oct 22nd, 2017
check_circle