The population of a certain city was 146,000 in 2006, and the observed doubling time for the population is 18 years.
Thank you for the opportunity to help you with your question!
(d) n(t) = 146,000 (2^(t/18))
500,000 = 146,000 (2^(t/18))
500,000/146,000 = 2^(t/18)
ln (500,000/146,000) = (t/18) ln 2
t = [ ln (500,000/146,000) ] / [ ln 2 ] x 18
This will occur during the year 2006 + 32 = 2038.
it actually 2037
That might be rounding issue. I kept all the numbers original and round it at the end.
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?