A 15-g sample of radioactive iodine decays in such a way that the mass remaining after t days is given by
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5 = 15exp(-0.079t)
exp(-0.079t) = 5/15=1/3
-0.079t = ln(1/3)
t = - ln(1/3)/0.079
= 13.906 days
Hence, 5 gm will remain after 13.906 days.
We can say t = 14 days.
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