A 15-g sample of radioactive iodine decays in such a way that the mass remaining after t days is given by

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5 = 15exp(-0.079t)

exp(-0.079t) = 5/15=1/3

-0.079t = ln(1/3)

t = - ln(1/3)/0.079

= 13.906 days

Hence, 5 gm will remain after 13.906 days.

We can say t = 14 days.

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