Chemistry question, What is the specific heat of the metal?

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A sample of an unknown metal has a mass of 58.932 g.  It has been heated to 101.00 degree C. then dropped quickly intgo 45020 mL if pure water.  The temperature of the water changed from 21.00 degree C to 23.68 degree C.  What is the specific heat of the metal? (Specific heat of water is 40184 J/g degree C)

Oct 19th, 2017

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heat given = heat absorbed 
specific heat metal(m) x change in temp(m) x mass(m) = specific heat(H20) x change in temp(H20) x mass(H2O) 

specific heat metal = unknown 
change in temp(m) = 100 - 32.3 = 67.7C 
change in temp(H2O) = 32.3 - 20.7 = 11.6C 
mass(m) = 27.2 grams 
mass(H2O) = 25.1 grams 
specific heat(H2O) = 1 cal/gram*C 

specific heat of metal = (1 x 11.6 x 25.1) / (67.7 x 27.2) 
= 0.158 cal/gram*C ----> answer 

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