when graphing in standard form how to solve for 10x-3y= -15

Algebra
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how to plot equation on a graph when graphing lines in standard form

Jul 16th, 2015

Thank you for the opportunity to help you with your question!

 standard from of equation 

y = mx + c

here m is slope and c is y intercept

10 x - 3y = -15

  3 y = 10 x  + 15

  y = 10x /3 + 15 /3

 y = 10 x /3 +  5


camparing this with standard equation

slope ,m = 10 /3  and y intercept = 5


so plot a graph with slope 10 / 3 and passing through 5 on y axis(that is point(0,5))


grapher (1).gif


this is the graph with slope 10 /3 and passing through ( 0,5)



Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 16th, 2015

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