Description
A quadratic function is given.
f(x) = 2x2 + 6x
(a) Express the quadratic function in standard form.
(b) Find its vertex and its x- and y-intercept(s). (If an answer does not exist, enter DNE.)
f(x) = | 2x2+6x=0 |
(b) Find its vertex and its x- and y-intercept(s). (If an answer does not exist, enter DNE.)
vertex | (x, y) = | −32 , −92 | ||
x-intercepts | (x, y) = | 3 |
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Explanation & Answer
Thank you for the opportunity to help you with your question! the solution is as such:
The standatd form is y= 2( x + 1.5)^2 - 2.25
The vertex is (-1.5 , - 2.25)
The x intercept is - 0.75
The y intecept is = 2.25
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