Evaluate the expression. (a) 2log2 20 (b) 5log5 32 (c) eln

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Evaluate the expression.
2log2 20

5log5 32

Nov 17th, 2017

Thank you for the opportunity to help you with your question!

Let's remember this logaritmic property:

a^( log a (x) ) = x . The base a cancels out with the log of base a leaving just its argument (the x).  

Then we would have:

a) 2^( log 2 (20) ) = 20

b) 5^(log 5 (32) ) = 32

c) e^(ln sqrt(11) ) = sqrt(11)

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 17th, 2015

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