Physics question 4 hw 22

label Physics
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

1. Calculate the total binding energy of 20 10Ne. Answer in units of MeV.

2. Calculate the total binding energy of 40 20Ca. Answer in units of MeV.

Oct 17th, 2017

Thank you for the opportunity to help you with your question!

1. 

Correct answer: 160.651 MeV. 

Explanation: Let : ZNe−20 = 10 , ANe−20 = 20 , mNe−20 = 19.992435 u ,

mH = 1.007825 u , mn = 1.008665 u , and c 2 = 931.50 MeV/u .

N = A − Z = 20 − 10 = 10 

∆m = Z mH + N mn − mNe−20 

= 10 (1.007825 u) + 10 (1.008665 u) − 19.992435 u

 = 0.172465 u , so Ebind = (0.172465 u)(931.50 MeV/u) = 160.651 MeV .


2.

Correct answer: 342.055 MeV.

 Explanation: Let : ZCa−40 = 20 , ACa−40 = 40 , and mCa−40 = 39.962591 u .

 N = 40 − 20 = 20

∆m = Z mH + N mn − mCa−40 

= 20 (1.007825 u) + 20 (1.008665 u) − 39.962591 u

 = 0.367209 u , 

so Ebind = ∆m c2 = (0.367209 u)(931.50 MeV/u) = 342.055 MeV .

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 17th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
Oct 17th, 2017
...
Oct 17th, 2017
Oct 18th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer