Physics question 3 hw 22

Physics
Tutor: None Selected Time limit: 1 Day

Find the binding energy of carbon-12 per nucleon. The mass of a proton is 1.007276 u, of a neutron 1.008665 u, and of carbon 11.996706 u.

1. 11167.2 MeV 

2. 92.1626 MeV 

3. 7.68022 MeV 

4. 11182.7 MeV 

6. 1870.17 MeV 

7. 22442 MeV 

8. 5166.74 MeV

The answer is NOT 931.891

Jul 17th, 2015

Thank you for the opportunity to help you with your question!

ΔΕ = (Δm)c^2 

1 u = 931.5 MeV/c^2 

c^2 = 931.5 MeV/u 

ΔΕ =[(Zmp + Nmn) - mc](931.5 MeV/u) 
ΔΕ = {[(6)(1.007276 u) + (6)(1.008665 u)] - 11.996706 u}(931.5 MeV/u) 

ΔΕ = 92.16 MeV

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 17th, 2015

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