determine the dimensions of the enclosure that can be erected at minimum cost

Calculus
Tutor: None Selected Time limit: 1 Day

Jul 17th, 2015

Thank you for the opportunity to help you with your question!

Let steel side be y feet and wood side be x feet.

Cost C = 5*(x+x)+3y= 10x+3y

xy = 920 giving = 920/x

Hence, C = 10x+3*920/x

dC/dx = 10 -3*920/x^2 = 0 foe minimum cost

Or, x = sqrt(2*92) =16.613

y = 920/16.613 = 55,377

Hence, wood side = 16.6 feet and steel side = 55.4 feet.         Ans.

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 17th, 2015

I considered area as 920. I think it is 929.

In that case, wood side = 16.7 ft and steel side = 55.6 ft.

Jul 17th, 2015

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