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The Perimeter is distance all round the shape and it is 20ft
The shape is in fom of a tectangle attached to a semi circle which means the perimeter can be given by
p=2y+2x +x *pi
remember the length of a curve is given by a half ( since its a semicircle) times 2 times pi times the radius and our radius is x
Let Pi be 3.14
20=2y+2x + ( 3.14x)
20=2y + 5.14x
hight y= 20/2 - 5.14x/2
y=10 - 2.57x
Area= semicircle + rectangle
A= 1/2 pi * radius ^2 + y *2x
A=0.5 * 3.14 * x^2 + 2xy
Replace the y with 10-2.57x
A= 0.5 *3.14 * x^2 + 2x (10-2.57x)
I am working on the last part and will submit it shortly
can you please provide a clear y= and x=
perimeter of semicircle= 1/2 pi * Diameter
=1/2 * 3.14 * 2x
Group like terms together
A=20x - 3.57x^2
Find the max area by finding the axis of symmetry; x = -b/(2a)
x= 2.80112 ft
y= 10 - 2.57x
Area= 20x -5.14x^2 + 3.14x^2
A=20(2.80112) -5.14 (2.80112)^2 +3.14 (2.80112)^2
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