Find the average cost function C. plus two word based problems

Calculus
Tutor: None Selected Time limit: 1 Day

Jul 17th, 2015

Thank you for the opportunity to help you with your question!

(a) Average cost A = C/x = 0.000002x^2+5+456/x

(b) dA/dx = 0.000002*2x-456/x^2 = 0

x = (456/0.000002*2)^(1/3) = 484.88, say, 485

(c)0.000002x^2+5+456/x = 0.000002*3x^2+5

Solving it, we get x = 484.88, say 485

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 17th, 2015

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