x > 2, then x2 – x – 6 i know that this factors into (x - 3)(x + 2) over (x - 2)(x+2) but where di

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x > 2, then x2 – x – 6 i know that this factors into (x - 3)(x + 2)  over  (x - 2)(x+2) but where did the -x from the x2-x-6 go? i can understand why x2-6 would factor in to (x-3)(x+2) because theres 2 x's that get a spot in the factor. but it seems the -x has just disapired! 

Jul 17th, 2015

Thank you for the opportunity to help you with your question!

x^2-x-6  if you factorize

you first multiply -6*x^2=-6x^2

look for two factors when you multiply you get -6x^2 and when you add those two factors you get -x

the factors are -3x and 2x so this two factors will represent -x

x^2-3x+2x-6  here -x has been replaced by -3x and 2x





 and when (x+2)(x-3)  is divided by  (x-2)(x+2)  

(x+2) will cancel in the numerator and denominator and the final answer will be 


Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 17th, 2015

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