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Differentiate f(x) w.r.t. x

Put f'(x) = 0

So, we have two critical points x = 0 and x = -2.

Since x = -2 does not lie in the interval [-1, 2], it can be ignored.

Now to find the absolute maximum and minimum in [-1, 2] we have to evaluate the value of the function at the critical point and at the end points.

So, absolute maximum of f(x) is 26 which occurs at x = 2 (an endpoint)

and absolute minimum of f(x) is 6 which occurs at x = 0 (a critical point)

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