Help Calculus Problem

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zngu fybj

Mathematics

Description

equation of the tangent line at x=1 for f(x)=2sqrtx/4x^2-5

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Explanation & Answer

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for x=1 for f(x)=2sqrtx/4x^2-5,

the gradient=2/(4-5)

=-2

y=-2x + 2

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Anonymous
I was having a hard time with this subject, and this was a great help.

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