Help Calculus Problem

Calculus
Tutor: None Selected Time limit: 1 Day

equation of the tangent line at x=1 for f(x)=2sqrtx/4x^2-5

Jul 22nd, 2015

Thank you for the opportunity to help you with your question!

for x=1 for f(x)=2sqrtx/4x^2-5,

the gradient=2/(4-5)

=-2

y=-2x + 2

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 22nd, 2015

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Jul 22nd, 2015
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Jul 22nd, 2015
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