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1. substituting x =2 we get 0/0 format therefore we can use L hospital rule as follows

(Differentiating Numerator and denominator separately)

lim x->2 (2x-2)/(2x-1) now substitute x =2 we get (4-2)/(4-1) = 2/3 (Answer)

2.

substituting x = infinite , we get infinite/infinite , format therefore we can use L hospital rule as follows

(Differentiating Numerator and denominator separately)

lim x->infinite 4x/(6x-5) take out x common from denominator we get 4x/x(6-5/x)

and solving we get ; 4/(6-5/x) now substitute x =infinite we get 4/(6-0) = 2/3 (Answer)

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