##### Calculus Problem- need help!

label Calculus
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schedule 1 Day
account_balance_wallet \$5

Determine the exact value

1. lim x->2 (x^2-2x/x^2-x-2)

2. lim x->infinite (2x^2/3x^2-5x+3)

Jul 22nd, 2015

1.  substituting x =2 we get  0/0 format therefore we can use L hospital rule as follows

(Differentiating Numerator and denominator separately)

lim x->2      (2x-2)/(2x-1)   now   substitute x =2 we get  (4-2)/(4-1) = 2/3 (Answer)

2.

substituting x = infinite ,  we get  infinite/infinite ,   format therefore  we can use L hospital rule as follows

(Differentiating Numerator and denominator separately)

lim x->infinite      4x/(6x-5)   take out x common from denominator we get 4x/x(6-5/x)

and solving we get ;   4/(6-5/x)       now  substitute x =infinite  we get  4/(6-0) = 2/3 (Answer)

(I am good in performing online assignments too .... )

Please find the solution enclosed here with. In case of any doubt please feel free to ask … If you need help in any assignment of math/ science … any online exam / discussion, Please contact for quick & quality services.
Jul 22nd, 2015

is this alright ???

Jul 22nd, 2015

Yes, thank you so much!

Jul 22nd, 2015

i am good in online works like Webassign, xyz , Mathlab also .... you may contact me if needed

Jul 22nd, 2015

Absolutely! Thanks

Jul 22nd, 2015

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Jul 22nd, 2015
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Jul 22nd, 2015
Oct 22nd, 2017
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