Calculate the number of grams of each of the following present in the mixture:

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Solutions of sulfuric acid and lead(II) acetate react to form solid lead(II) sulfate and a solution of acetic acid. If 9.00 g of sulfuric acid and 9.00 g of lead(II) acetate are mixed, calculate the number of grams of each of the following present in the mixture after the reaction is complete:

a) Sulfuric Acid

b) lead(II) acetate

c) lead(II) sulfate

d) acetic acid

Jul 22nd, 2015

Thank you for the opportunity to help you with your question!

H2SO4 + Pb(OAc)2 --> PbSO4 + 2HOAc 
9 g H2SO4 = 9g / 98.08g/mole =0.09176 moles H2SO4 
9 g HOAc = 9g / 325.3g/mole = 0.02767 moles of Pb(OAc)2 
After mixing- 
0.02767 moles of PbSO4 
0.05534 mole of HOAc 
0.00000 mole of Pb(OAc)2 
0.09176-0.02767= 0.06409 moles of H2SO4 
0.06409 moles x 98.08 g/mole = 6.29 g H2SO4

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 22nd, 2015

You seem to have just copy and pasted a "yahoo answers post" in order to answer my question, which was not even answered completely.

I would like you to reread my question please and try again. I am looking for the gram value of 4 different substances. Not to mention the formulas were also off.

Jul 22nd, 2015

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