##### Calculate the number of grams of each of the following present in the mixture:

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Solutions of sulfuric acid and lead(II) acetate react to form solid lead(II) sulfate and a solution of acetic acid. If 9.00 g of sulfuric acid and 9.00 g of lead(II) acetate are mixed, calculate the number of grams of each of the following present in the mixture after the reaction is complete:

a) Sulfuric Acid

d) acetic acid

Jul 22nd, 2015

H2SO4 + Pb(OAc)2 --> PbSO4 + 2HOAc
9 g H2SO4 = 9g / 98.08g/mole =0.09176 moles H2SO4
9 g HOAc = 9g / 325.3g/mole = 0.02767 moles of Pb(OAc)2
After mixing-
0.02767 moles of PbSO4
0.05534 mole of HOAc
0.00000 mole of Pb(OAc)2
0.09176-0.02767= 0.06409 moles of H2SO4
0.06409 moles x 98.08 g/mole = 6.29 g H2SO4

Jul 22nd, 2015

You seem to have just copy and pasted a "yahoo answers post" in order to answer my question, which was not even answered completely.  https://answers.yahoo.com/question/index?qid=20070919194342AAG2Vf9

I would like you to reread my question please and try again. I am looking for the gram value of 4 different substances. Not to mention the formulas were also off.

Jul 22nd, 2015

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Jul 22nd, 2015
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Jul 22nd, 2015
Sep 23rd, 2017
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