What happens to the
pressure inside a rigid container if the amount of nitrogen gas increases from
0.500 mole to 0.750 mole? The original pressure is 98.0 kPa, and the
temperature remains constant.
Thank you for the opportunity to help you with your question!
Use Ideal gas equation:
PV = n/MM RT
As V, MM, R, and T are constant, so P is directly proportional to n
P1/n1 = P2/n2
98.0 / 0.500 = P2 / 0.750
P2 = 98.0 / 0.500 x 0.750
= 147 kPa
The pressure is increased from 98 kPa to 147 kPa.
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