Determine the area enclosed by the curves f(x)=x^2-2x and g(x)=4-x^2

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solve f = g

x^2-2x = 4-x^2

x^2 -x -2 =0

x =-1, x = 2

A = integrate of (g-x)dx = (4-x^2-x^2+2x) dx= (4-2x^2+2x) dx from -1 to 2

4x-2/3x^3 +x^2

= 8-16/3 +4 +4+2/3-1 = 31//3

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