number of O atoms in 4.12 10-3 mol Al(NO3)3

Chemistry
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What art thy number of O atoms in 4.12  10-3 mol Al(NO3)3  ?

Jul 22nd, 2015

Thank you for the opportunity to help you with your question!

number of O atoms =6.022*10^23 *4.12 *10^-3

                                 =24.8106 *10^20

                                 =2.4810e21

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 22nd, 2015

number of O atoms =9 *2.4810e21

                                 =22.329e21

                                =2.2329e22

Jul 22nd, 2015

Could you explain it with words please, im kind of confused :/

Jul 22nd, 2015

1 mole of Al(NO3)3  contains 9*6.022 *10^23 atoms of oxygen (since 1 molecule contains 9 O attoms)

number of O atoms in  4.12 *10^-3 mole of Al(NO3)3 =9*6.022*10^23 *4.12 *10^-3

                                 =2.2329e22 atoms of O


Jul 22nd, 2015

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