What art thy number of O atoms in 4.12 10-3 mol Al(NO3)3 ?
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number of O atoms =6.022*10^23 *4.12 *10^-3
number of O atoms =9 *2.4810e21
Could you explain it with words please, im kind of confused :/
1 mole of Al(NO3)3 contains 9*6.022 *10^23 atoms of oxygen (since 1 molecule contains 9 O attoms)
number of O atoms in 4.12 *10^-3 mole of Al(NO3)3 =9*6.022*10^23 *4.12 *10^-3
=2.2329e22 atoms of O
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