The half-life a particular isotope of barium is 12 s. What is the activity of a 1.0 × 10^{–6} kg sample of this isotope?

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N = N0(1/2)^(t/12) Ln(N/N0) = - (t/12)ln(2) Ln(N/N0) ≈ - 0.0578t N ≈ N0e^- 0.0578t dN/dt ≈ - 0.0578N0e^- 0.0578t dN/dt ≈ (0.0578)(10^-6 kg)(6.02*10^23/mol)(1 mol/0.143922953 kg) dN/dt ≈ 2.5*10^17 Bq

ANSWER:

4) 2.5 x 10^17 Bq

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