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f'(x) = 9x^2 -12x+7

f(x) = 3x^3-6x^2 +7x +c

at x =1 f(x) = 10 hence

10 = 3-6+7+c ; or c = 6

hence f(x) = 3x^3-6x^2 +7x +6

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Jul 23rd, 2015

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