Give the empirical formula of each of the following compounds if a sample contains the following quantities of each element:

a) 0.0418 mol iron and 0.0418 mol oxygen

b) 16.8 g C, 1.20 g H, and 6.40 g O

c) 48.6% C, 8.16% H, and 43.2% O by mass

a) 0.0418 mol Fe : 0.0418 mol O = 1 : 1

Therefore, the empirical formula is FeO.

b) 16.8 g C = 1.4 mol C

1.20 g H = 1.19 mol H

6.40 g O = 0.4 mol O

0.0833 mol C : 1.19 mol H : 0.4 mol O = 7 : 6 : 2

Therefore, empirical formula = C_{7}H_{6}O_{2} .

c) calculation.png

4.05 mol C : 8.10 mol H : 2.70 mol O = 3 : 6 : 2

Therefore, empirical formula = C_{3}H_{6}O_{2} .

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