Give the empirical formula of each of the following compounds if a sample contains the following quantities of each element:
a) 0.0418 mol iron and 0.0418 mol oxygen
b) 16.8 g C, 1.20 g H, and 6.40 g O
c) 48.6% C, 8.16% H, and 43.2% O by mass
a) 0.0418 mol Fe : 0.0418 mol O = 1 : 1
Therefore, the empirical formula is FeO.
b) 16.8 g C = 1.4 mol C
1.20 g H = 1.19 mol H
6.40 g O = 0.4 mol O
0.0833 mol C : 1.19 mol H : 0.4 mol O = 7 : 6 : 2
Therefore, empirical formula = C7H6O2
4.05 mol C : 8.10 mol H : 2.70 mol O = 3 : 6 : 2
Therefore, empirical formula = C3H6O2
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?