Calcium hydride reacts with water to form calcium hydroxide and hydrogen gas.
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6.4919/1.008= 3.22moles of hydrogen used.
For I mole of calcium hydride, 2 moles of hydrogen was formed hence the amount of calcium hydride used in moles is 3.22/2=1.61 moles of calcium hydride.
Hence mass= moles *molar mass which is 1.61moles*42.094= 67.77g
Hence 67.77g of calcium hydride was used.
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