Solving for amount of moles grams etc

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The complete combustion of octane, C8H18, the main component of gasoline, proceeds as shown below.

2 C8H18(l) + 25 O2(g) → 16 CO2(g) + 18 H2O(l)

(a) How many moles of O2 are needed to burn 1.00 mol of C8H18

(b) How many grams of O2 are needed to burn 1.75 g of C8H18

(c) Octane has a density of 0.692 g/mL at 20°C. How many grams of O2 are required to burn 3.35 gal of C8H18?

Jul 24th, 2015

Thank you for the opportunity to help you with your question!

a) ratio=2:25

=25x1/2

=12.5 moles

b) 12x8 + 18=114

=32x1.75/114

=0.4912g

c)mass=density x volume

=0.692x3.35

=2.3182g

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 24th, 2015

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