##### Solve the system of equations by the substitution method

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-x+2y=5

-2x+3y=9

Jul 24th, 2015

-x+2y=5        -----> 1

-2x+3y=9      ------> 2

To eliminate x, multiply eq.1 by 2 to make the coefficeints of x equal

-2x+4y=10        -----> 3

-2x+3y=9      ------> 2

Subtract 3 from 2,

y = 1

So Substituting  the yalue of 'y' in eq.1 we get,

-x + (2*1) = 5

-x + 2 = 5

-x = 3

So x = -3

y = 1

Jul 24th, 2015

I am sorry... the above method was elimination method.

Jul 24th, 2015

-x+2y=5        -----> 1

-2x+3y=9      ------> 2

From eq.1 x = 2y-5

-2 (2y-5) +3y = 9

-4y+10+3y = 9

-y+10 = 9

-y = -1

y =1

So Substituting  the yalue of 'y' in eq.1 we get,

-x + (2*1) = 5

-x + 2 = 5

-x = 3

So x = -3

y = 1

Jul 24th, 2015

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Jul 24th, 2015

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Jul 24th, 2015
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Jul 24th, 2015
Sep 19th, 2017
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